目錄

• 前言

前言

本篇可當做例題練習,

1.查詢比”林紅”年紀大的男學生信息
語句:

select *from Studentwhere Sex="男" and 	year(Birth)-(select year(Birth)from Student--這里是需要告訴查詢的表名,相當于嵌套	where Sname="林紅")<0

2.檢索所有學生的選課信息,包括學號、姓名、課程名、成績,性別.
語句:

select sc.sno,sname, course.Cno,Cname,Grade,Sex--這里如果兩個表中都有同一個屬性,則需要標明在哪個表,如sc.snofrom student,sc,Coursewhere student.Sno=sc.Sno and Sc.Cno=course.Cno

3.查詢已經(jīng)選課的學生的學號、姓名、課程名、成績.
語句:

select sc.sno ,sname , Cname , Gradefrom student s , course c, scwhere s.sno=sc.sno and c.cno=sc.cno

(4)查詢選修了“C語言程序設(shè)計”的學生的學號與姓名
–a.用內(nèi)連接查詢
語句:

select sc.Sno,sname from student inner join sc onstudent.Sno=sc.Sno inner join course on sc.Cno =course.cnoand Cname="C語言程序設(shè)計"

–b.用連接查詢
語句:

select sc.Sno,sname from student,sc,course wherestudent .Sno=sc.Sno and sc.Cno =course.cnoand Cname="C語言程序設(shè)計"

–c.用子查詢
語句:

select Sno,sname from student where Sno in(select Sno from sc where Cno=(select cno from course where Cname ="C語言程序設(shè)計"))

(5)查詢與”張虹”在同一個班級的學生學號、姓名、家庭住址
–a．用連接查詢
語句:

select a.Sno,a.sname,a.Home_addr from student a,student b where a.Classno =b.Classno and b.Sname ="張虹" and a.Sname!="張虹"

–b．用子查詢
語句:

select Sno,sname,Home_addr  from student whereclassno=(select classno from student where sname="張虹")and sname!="張虹"

(6)查詢其他班級中比”051”班所有學生年齡大的學生的學號、姓名
代碼1:

select Sno,sname,Home_addr  from student whereclassno!="051" and Birth<all (select Birth  from student where classno="051")

代碼2:

select Sno,sname,Home_addr  from student whereclassno!="051" and Birth<(select min(Birth)  from student where classno="051")

(7）(選作)查詢選修了全部課程的學生姓名。本題使用除運算的方法。
–由題意可得另一種語言，沒有一個選了課的學生沒有選course表里的課程。那么，我們需要兩個NOT EXISTS表示雙重否定;
語句:

select Sname from studentwhere not exists (select * from coursewhere not exists (select * from scwhere sno=student. snoand cno=Course.cno))

(8）查詢至少選修了學生“20110002”選修的全部課程的學生的學號，姓名。
語句:

select Sno, Sname from studentwhere sno in (select distinct sno from sc as sc1where not exists (select * from sc as sc2 where sc2.sno="20110002"and not exists (select * from sc as sc3 where sc3.Sno=sc1.sno andsc3.cno=sC2.cno) ))

(9）檢索選修了“高數(shù)”課且成績至少高于選修課程號為“002"課程的學生的學號、課程號、成績，并按成績從高到低排列。
語句:

select sc.Sno, sc.cno , grade from sc wheregrade >all(select grade from sc where cno="002" ) andCno= (select Cnofrom course where Cname="高數(shù)")order by Grade desc

(10)檢索選修了至少3門以上課程的學生的學號、總成績(不統(tǒng)計不及格的成績)，并要求按總成績降序排列。
語句:

select sno,SUM(grade) from sc where sno in (select Sno from sc group by snohaving COUNT(*)>=3) and Grade>=60 group by snoorder by SUM (grade) desc

(12）檢索多于3名學生選修的并以3結(jié)尾的課程號的平均成績。
語句:

select avg(Grade) as 平均成績from scwhere Cno like "%3" group by cnohaving count (Cno)>3

(13）檢索最高分與最低分之差大于5分的學生的學號、姓名、最高分、最底分。

select distinct sc.sno 學號,sname 姓名,max (grade) as最高分,min (grade) as最低分from student,scwhere sc.sno=student.Sno group by sc.sno , Snamehaving max(grade) -min (grade) >5

(14)創(chuàng)建一個表Student_other，結(jié)構(gòu)同student,輸入若干記錄，部分記錄和student表中的相同。
–創(chuàng)建過程:

create table student__other (Sno char (8) primary key,Sname varchar (8) not null,sex char(2) not null,Birth smalldatetime not null,Classno char (3) not null,Entrance_date smalldatetime not null,Home_addr varchar (40) ,sdept char (2) not null,Postcode char (6))

隨意插入幾條student表中沒有的數(shù)據(jù):

–a.查詢同時出現(xiàn)在Student表和student_other表中的記錄
語句:

select * from student__other so ,student swhere so.sno=s.sno

----b．查詢Student表和Student_other表中的全部記錄
代碼:

select * from studentunionselect * from student__other

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